Matematika Sekolah Menengah Atas tentuka integral atas2 bawah 1 (x²+x+1)dx​

bethelkozeyulv – March 09, 2023

tentuka integral atas2 bawah 1 (x²+x+1)dx​

Jawaban:

29/6

Penjelasan dengan langkah-langkah:

[tex] { \int}^{2} _{1} \: {x}^{2} + x + 1 \: dx \\ = \frac{1}{3} {x}^{3} + \frac{1}{2} {x}^{2} + x { | }^{2} _{1} \\ = (\frac{1}{3} ( {2}^{3} ) + \frac{1}{2} ( {2}^{2} ) + 2) - ( \frac{1}{3} ( {1}^{3} ) + \frac{1}{2} ( {1}^{2} ) + 1) \\ = ( \frac{8}{3} + 2 + 2) - ( \frac{1}{3} + \frac{1}{2} + 1) \\ = \frac{7}{3} + \frac{3}{2} + 1 \\ = \frac{23}{6} + 1 \\ = \frac{29}{6} [/tex]

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