tentukan himpunan penyelesaian SPLDV berikut x+2y=3 x+3y=4
[tex]x + 2y = 3 \\ x + 3y = 4 \: \: \: ( - ) \\ - - - - - - \\ - y = - 1 \\ y = 1 \\ \\ x + 2y = 3 \\ x + 2 = 3 \\ x = 1 \\ \\ hp = (1,1)[/tex]
Jawab:
{x, y} = {1, 1}
Penjelasan :
x + 3y = 4
x + 2y = 3
--------------- (-)
--> y = 1
x + 2y = 3
x + 2(1) = 3
x + 2 = 3
x = 3 - 2
--> x = 1
(xcvi)
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